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TU Wien:Statistik und Wahrscheinlichkeitstheorie UE (Bura)/Übungen 2019W/8.2
(edit)
Revision as of 11:17, 3 December 2019
201 bytes added
,
11:17, 3 December 2019
→Lösungsvorschlag
Line 12:
Line 12:
load('waitingtimes2.Rdata')
load('waitingtimes2.Rdata')
par(mfrow=c(2,1))
par(mfrow=c(2,1))
−
hist(unlist(
wt[1]
))
+
x =
wt
[
[1]
]
−
hist(unlist(
wt[2]))
+
y =
wt
[
[2]
]
+
hist(x
)
+
hist(y
)
</syntaxhighlight>
</syntaxhighlight>
−
b)
TBD
+
b)
−
c)
TBD
+
<syntaxhighlight lang=r>
+
semx = sd(x)^2/length(x)
+
semy = sd(y)^2/length(y)
+
+
t = (mean(x) - mean(y))/sqrt(semx + semy)
+
t
+
+
pnorm(t)*2
+
</syntaxhighlight>
+
+
c)
+
<syntaxhighlight lang=r>
+
t.test(x,y)
+
</syntaxhighlight>
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