Editing TU Wien:Mathematik 1 UE (diverse)/Übungen WS07/Beispiel 1

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[http://de.wikipedia.org/wiki/Wurzel_3#Beweis_der_Irrationalit.C3.A4t Wikipedia Erklärung]
[http://de.wikipedia.org/wiki/Wurzel_3#Beweis_der_Irrationalit.C3.A4t Wikipedia Erklärung]
Auch: warum soll der Ansatz falsch sein ab (Setzen p=3r).
Dann hast du 9q^2=(3r)^2
und weiters 9q^2=9r^2
daraus ergibt sich q=r, wahre Aussage.
da p immer 3r ist, wäre die abfolge der brüche hier 3/1, 6/2, 9/3, was alles der Wurzel aus 9 entspricht.

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