TU Wien:Statistik und Wahrscheinlichkeitstheorie UE (Bura)/Übungen 2019W/3.2
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Suppose a train is delayed by approximately 60 minutes. Assuming that a uniform distribution (0, 60) was used to model the delayed time (in minutes), compute the probability that train will reach its final destination in the interval between 57 and 60 minutes. Calculate the expectation and standard deviation of the delayed time.
Lösungsvorschlag von Beku[Bearbeiten | Quelltext bearbeiten]
--Beku 11:31, 28. Okt. 2019 (CET)
Probability that train will reach its final destination in the interval between 57 and 60 minutes = 3/60 = 1/20 =
> 1 - punif(57, min=0, max=60) [1] 0.05
Expectation:
Standard Deviation:
Formeln für Erwartungswert und Varianz sind aus den Folien, man kann sie aber recht trivial auch selber berechnen.