TU Wien:Statistik und Wahrscheinlichkeitstheorie UE (Bura)/Übungen 2019W/5.2
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- (2) Boxplot
Two novel randomized algorithms (A and B) are to be compared regarding their running time. Both algorithms were executed n times. The running times (in seconds) are stored in the file runningtimes.csv.
- (a) Set the working directory and load the data using
read.csv()
. Create a boxplot to compare the running times. Color the boxes and add proper notations (axes notations, title etc.). More info via?boxplot
- (b) Comment on the following statements / questions only using the graphic
- (a) The first quartile of the times in A was about?
- (b) the interquartile range of the times in B is about trice the interquartile range of A
- (c) Is n = 100?
- (d) More than half of the running times in B were faster than 3/4 of the running times in A
- (e) At least 50% in A were faster than the 25% slowest in B
- (f) At least 60% in A were faster than the 25% slowest in B
Lösungsvorschlag von Draggy[Bearbeiten | Quelltext bearbeiten]
(a) Laden des Datasets :
runningtimes = read.csv('runningtimes.csv')
Boxplot erstellen:
boxplot(runningtimes, ylab = "Runtime", col=8)
(b)
- (a) The first quartile of the times in A was about?
- (b) the interquartile range of the times in B is about trice the interquartile range of A
- Ja. In der Angabe ist wohl ein Typo (trice => twice).
- (c) Is n = 100?
- Der Boxplot gibt keine Auskunft über die Größe der Datenmenge.
- (d) More than half of the running times in B were faster than 3/4 of the running times in A
- Stimmt, der Median von B liegt tiefer als das 1. Quantil von A.
- (e) At least 50% in A were faster than the 25% slowest in B
- Stimmt, da das 3. Quantil von B höher liegt als der Median von A.
- (f) At least 60% in A were faster than the 25% slowest in B.
StimmtKann nicht bestimmt werden - Die Elemente im dritten Quartil müssen nicht gleichmäßig angeordnet sein, dadurch kann nicht festgestellt werden, wie viele Elemente unter der Grenze liegen.