TU Wien:Statistik und Wahrscheinlichkeitstheorie UE (Bura)/Übungen 2020W/HW11.5
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Regression (part 2)[Bearbeiten | Quelltext bearbeiten]
Continuation of exercise 4: Assume the linear regression model , with i.i.d. and , and . Test the null hypothesis (without lm()
) at a significance level of 5%.
- a) Compute the standard error of the regression .
- b) Compute the standard error , of the slope .
- c) Compute the value of the -statistc.
- d) Compute the -distribution associated with .
- e) Compute the -value.
- f) Formulate a result.
Lösungsvorschlag von Friday[Bearbeiten | Quelltext bearbeiten]
--Friday Sa 30 Jan 2021 19:47:45 CET
5a)[Bearbeiten | Quelltext bearbeiten]
calc_sr <- function(x,y,b0,b1) {
n <- length(x)
result <- 0
# Create the sum
for (i in 1:n) {
result <- result + (y[i] - (b0 + b1 * x[i]))^2
}
result <- sqrt(result /(n-2))
}
sr <- calc_sr(x, y, b0, b1) # 8.762359
5b)[Bearbeiten | Quelltext bearbeiten]
n <- length(x)
seb <- sr/(sx * sqrt(n - 1)) # 0.08110709
5c)[Bearbeiten | Quelltext bearbeiten]
t <- (b1-0)/seb # 2.864922
5d)[Bearbeiten | Quelltext bearbeiten]
alpha <- 0.05
q1 <- qt(1-alpha/2, df=n-2) # 2.068658
I <- c(b1-q1*seb, b1+q1*seb) # 0.0645827 0.4001483
5e)[Bearbeiten | Quelltext bearbeiten]
p <- pt(-t, df=n-2) * 2 # 0.0087558512
5f)[Bearbeiten | Quelltext bearbeiten]
The observed postive realation in the data is barely compatible with the null-hypothesis that there is no realation. If holds true we observed a case which occourse under of the cases.